Hi, there-- Problem: Graphand give the domain and range. Answer: Your domain and range are correct. The graph of looks exactly like the graph of except it is shifted 2 units to the left. The graph looks a little like a half a parabola laying on its side (opening to the right.) The graph of your equation intersects the x-axis at (-2,0). To get a sketch of the graph, make a quick (x,y) table: x y -2 0 -1 1 2 2 7 3 14 4 Remember that x≥2, and y≥0. You can see a picture of the graph if you google "graph y=sqrt(x+2)" (Don't include quotation marks.) Hope this helps! Feel free to email, if you still have questions. Mrs.Figgy