SOLUTION: Graph the following equation, using the intercept method. 2x + 3y = 6 I am a bit confusded on how to graph these since there are two variables. If I worked the problem right

Algebra ->  Algebra  -> Graphs -> SOLUTION: Graph the following equation, using the intercept method. 2x + 3y = 6 I am a bit confusded on how to graph these since there are two variables. If I worked the problem right      Log On

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Question 65765This question is from textbook Beginning Algebra
: Graph the following equation, using the intercept method.
2x + 3y = 6
I am a bit confusded on how to graph these since there are two variables. If I worked the problem right I came up with 1.
2x + 3y = 5

6-5 = 1
This is as far as I got. This question is from textbook Beginning Algebra

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
TRO PUT THESE EQUATIONS IN THE LINE FORM WE HAVE:
2X+3Y=6
3Y=-2X+6
Y=-2X/3+6/3
Y=-2X/3+2 THUS THIS LINE HAS A SLOPE OF -2/3 & A Y INTERCEPT OF 2
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2X+3Y=5
3Y=-2X=5
Y=-2X/3+5/3 THUS THIS LINE ALSO HAS A SLOPE OF -2/3 & A Y INTERCEPT OF 5/3
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-2%2F3X%2B2%2C+-2%2F3X%2B5%2F3%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions -2/3X+2 and
-2/3X+5/3).
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x-2%2C+x%5E2%2F10-x%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions x^2 and x^2/10-x).