SOLUTION: Graph the following equation, using the intercept method.
2x + 3y = 6
I am a bit confusded on how to graph these since there are two variables. If I worked the problem right
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Question 65765This question is from textbook Beginning Algebra
: Graph the following equation, using the intercept method.
2x + 3y = 6
I am a bit confusded on how to graph these since there are two variables. If I worked the problem right I came up with 1.
2x + 3y = 5
6-5 = 1
This is as far as I got.
This question is from textbook Beginning Algebra
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
TRO PUT THESE EQUATIONS IN THE LINE FORM WE HAVE:
2X+3Y=6
3Y=-2X+6
Y=-2X/3+6/3
Y=-2X/3+2 THUS THIS LINE HAS A SLOPE OF -2/3 & A Y INTERCEPT OF 2
-----------------------------------------------------------------------
2X+3Y=5
3Y=-2X=5
Y=-2X/3+5/3 THUS THIS LINE ALSO HAS A SLOPE OF -2/3 & A Y INTERCEPT OF 5/3
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions -2/3X+2 and
-2/3X+5/3).
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions x^2 and x^2/10-x).
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