SOLUTION: Solve each of the following systems by graphing. 2x – y = 4 2x –y = 6 Solve each of the following systems by graphing. X –2y = 8 3x –2y = 12 Solve each of the following s

Algebra ->  Algebra  -> Graphs -> SOLUTION: Solve each of the following systems by graphing. 2x – y = 4 2x –y = 6 Solve each of the following systems by graphing. X –2y = 8 3x –2y = 12 Solve each of the following s      Log On

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Question 65654: Solve each of the following systems by graphing.
2x – y = 4
2x –y = 6
Solve each of the following systems by graphing.
X –2y = 8
3x –2y = 12
Solve each of the following systems by graphing.
3x –6y = 9
X –2y = 3

Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
1. 2x – y = 4
2x –y = 6

ANSWER:
FIRST OF ALL REWRITE THESE EQUATIONS IN TERMS OF X,

==> 2x – 4 = y
2x –6 = y

Now give arbitrary values for x and find corresponding values of y.

Using these values plot the graph for these two equations.

Then the graph comes like this.



+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+2x-4%2C+2x-6%29+





Since two graphs are parellel, these two equations have no solution.



2. X –2y = 8

3x –2y = 12

Follow the same procedure as above,

we have equations,


y = x/2 -4 and

y = (3/2)x - 6


Now find out values of y corresponding the values of x.

Using these values plot the graph...


Then the graph comes like this,


+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%2F2+-4%2C+%283%2F2%29x-6%29+





Here two lines intersect at a point. Draw lines perpendicular to x axis and y axis.
At X axis we have the point 2 and on the Y axis we have -3
So solution for these equations is ( 2, -3)



3. 3x –6y = 9

X –2y = 3


Here equations become,

y = (1/2)x - 3/2 and

y =(x/2) - (3/2)

Find out values of x and y and plot the graph.

Then the graph cpmes like this,


+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F2%29x-3%2F2%2C+%28x%2F2%29-%283%2F2%29%29+



Here we can see that both the lines overlap each other,
that means two equations represent the same line.



Hope you Understood.


Regards.

praseenakos@yahoo.co.in