SOLUTION: Find the equation of the line satisfying the given conditions:
Is tangent to the circle 2x^2+2y^2-12x+16y=0 at the point (6,-8)
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Question 653881: Find the equation of the line satisfying the given conditions:
Is tangent to the circle 2x^2+2y^2-12x+16y=0 at the point (6,-8)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Complete the square for both variables in your equation for the circle:
1. Divide by the lead coefficient
^2\ +\ (y\ +\ 4)^2\ =\ 25)
Note that the center of the circle is at )
and that the radius is 5.
2. Find the slope of the line containing the radius segment from the center of the circle to the point of tangency.
}{3\ -\ 6})
You do your own arithmetic
3. Use the fact that any tangent to a circle is perpendicular to the radius at the point of tangency plus the fact that the slopes of perpendicular lines are negative reciprocals to calculate the slope of the desired line. 
4. Use the point-slope form of an equation of a line to derive the desired equation:
 )
where )
are the coordinates of the given point and 
is the slope calculated in step 3.
John
My calculator said it, I believe it, that settles it
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