Hi,

Find the coordinates of the vertex for the parabola defined by the given quadratic function. 

F(x)=7x^2+14x-3    |putting in Vertex form by completing the Square

F(x) = 7(x+1)^2 - 7 - 3

F(x) = 7(x+1)^2 - 10   V(-1,-10)

the vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  

Checking our Work

F(x) = 7(x+1)^2 - 10

F(x) = 7(x^2 + 2x + 1) - 10

F(x) = 7x^2 + 14x + 7 - 10

F(x) = 7x^2 + 14x -3 

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