SOLUTION: looking for more help please, Thank you... Given f(x) = x^2 � 8x - 20 equation (parabola), find the following: 21.) The vertex 22.) The y-intercept(s)

Question 64480: looking for more help please, Thank you...
Given f(x) = x^2 � 8x - 20 equation (parabola), find the following:
21.) The vertex
22.) The y-intercept(s)

Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
The easiest way to find the vertex of f(x)= ax^2 + bx + c is
In this case,

To find the y coordinate of the vertex, "Plug it in, plug it in!":

Vertex = (4, -36)
Y intercept is always where x=0, so y = -20.

R^2 at SCC
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