# SOLUTION: I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4. I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,

Algebra ->  Algebra  -> Graphs -> SOLUTION: I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4. I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,      Log On

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 Question 643877: I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4. I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,0). I am having trouble finding the intercepts for y. I substitute 0 for X and get 0 + y^3 + 4. I convert that to y^3 = -4. I am not sure where to go from there. Can I get a cube root of four? Solving for y, would my answer be the cube root of four i? Does that mean there is no y intercept? I've confused myself... Thanks for any help.Answer by MathTherapy(1483)   (Show Source): You can put this solution on YOUR website! I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4. I am starting by trying to find the intercepts. I think I found the intercepts for x - (2,0), (-2,0). I am having trouble finding the intercepts for y. I substitute 0 for X and get 0 + y^3 + 4. I convert that to y^3 = -4. I am not sure where to go from there. Can I get a cube root of four? Solving for y, would my answer be the cube root of four i? Does that mean there is no y intercept? I've confused myself... Thanks for any help. y-intercept = , or - 1.587401052 ≈ Send comments and “thank-yous” to “D” at MathMadEzy@aol.com