SOLUTION: The graph of the relation x^2 - 4y^2 + 2x - 8y - 10 = 0 is a (an) a. point b. straight line c. pair of intersecting straight lines d. circle e. ellipse f. hyperbola g. par

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Question 63902: The graph of the relation x^2 - 4y^2 + 2x - 8y - 10 = 0 is a (an)
a. point
b. straight line
c. pair of intersecting straight lines
d. circle
e. ellipse
f. hyperbola
g. parabola
h. none of these
Answer by algebrapro18(206) (Show Source):
You can put this solution on YOUR website!
You need to complete the square to get this equation into standard form and then see what it matches up to.

x^2 - 4y^2 + 2x - 8y - 10 = 0

x^2 + 2x - 4(y^2 - 2y) = 10

x^2 + 2x + 1 - 4(y^2 - 2y + 1) = 10+4+1

(x+1)^2 - 4(y-1)^2 = 15

((x+1)^2)/15 - (4(y-1)^2)/15 = 1

I can't remember if this is the standard form for an ellipse or a hyperbola but it is one of the two.