Hi,



Find the coordinates of the vertex for the parabola 

f(x)= -2x^2-2x.   

| completing the Square to find the Vertex: y = ax^2 + bx + c   ⇒ y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c

f(x) = -2(x+1/2)^2 + 1/2    V(-1/2,1/2)

the vertex form of a Parabola opening up(a>0) or down(a<0)is:  

where(h,k) is the vertex  



 

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