# SOLUTION: Find the vertex, focus, and directrix of the parabola given by the equation. Sketch the graph. (2x &#8722; 8)2 = 8y &#8722; 56

Algebra ->  Algebra  -> Graphs -> SOLUTION: Find the vertex, focus, and directrix of the parabola given by the equation. Sketch the graph. (2x &#8722; 8)2 = 8y &#8722; 56      Log On

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 Question 630371: Find the vertex, focus, and directrix of the parabola given by the equation. Sketch the graph. (2x − 8)2 = 8y − 56Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, (2x - 8)^2 = 8y- 56 2x^2 - 16x + 64 = 8y - 56 2(x-4)^2 -32 +64 = 8y - 56 2(x-4)^2 = 8y - 88 2(x-4)^2 = 8(y-11) (x-4)^2 = 4(y-11) 4p = 4, p = 1, V(4,11), F(4,12) directrix: y = 10 y = (1/4)(x-4)^2 + 11 line of Symmetry is x = 4 ```