SOLUTION: solve each by the substitution method.
Y=2x+6
3x-2y=-11
x+3y=-3
2x+y=4
Algebra.Com
Question 626365: solve each by the substitution method.
Y=2x+6
3x-2y=-11
x+3y=-3
2x+y=4
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve each by the substitution method.
Y=2x+6
3x-2y=-11
---
Substitute for "y" and solve for "x":
3x - 2(2x+6) = -11
3x - 4x - 12 = -11
-x = 1
x = -1
---
Solve for "y":
y = 2x+6
y = 2*-1+6
y = 4
-----------------
x+3y=-3
2x+y=4
----
Solve 1st for "y":
y = 4-2x
---
Substitute for "y" and solve for "x":
x + 3(4-2x) = -3
x + 12 - 6x = -3
-5x = -15
x = 3
---
Solve for "y":
y = 4-2x
y = 4-2*3
y = -2
==================
Cheers,
Stan H.
=====================
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