# SOLUTION: The equation of the line that goes through the point ( 5, 5 ) and is parallel to the line going through the points ( -4 ,6 ) and ( 2 ,4 ) can be written in the form y = mx+b where

Algebra ->  Algebra  -> Graphs -> SOLUTION: The equation of the line that goes through the point ( 5, 5 ) and is parallel to the line going through the points ( -4 ,6 ) and ( 2 ,4 ) can be written in the form y = mx+b where       Log On

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 Question 620465: The equation of the line that goes through the point ( 5, 5 ) and is parallel to the line going through the points ( -4 ,6 ) and ( 2 ,4 ) can be written in the form y = mx+b where m is and b is. I am struggling with this question i have no idea how to start this can you explain it in steps for me.Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, The equation of the line that goes through the point ( 5, 5 ) and is parallel to the line going through the points ( -4 ,6 ) and ( 2 ,4 ) m = 2/-6 = (-1/3) New Line: (same slope) y = mx + b y = (-1/3)x + b ||using Pt(5,5) to solve for b 5 = -5/3 + b 20/3 = b y = (-1/3)x + 20/3 ```