SOLUTION: for the function y=x^2-6x+8 put the function in the form y=a(x-h)^2 +k how do i do that and how do i graph it using the equation i got confused

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Question 58544: for the function y=x^2-6x+8 put the function in the form y=a(x-h)^2 +k
how do i do that and how do i graph it using the equation i got confused

Answer by funmath(2933)   (Show Source): You can put this solution on YOUR website!
for the function (standard form) put the function in the form (vertex form)
Group the x's
Add (-6/2)^2=(-3)^2=9 to the inside of the parenthesis and take it away from the outside, so you're adding 9-9=0 and not breaking any rules.
Now the parenthesis is a perfect square.

a=1 since it's positive and 1 the parabola opens up and is standard width.
The vertex is (h,k)=(3,-1)
So you have a general idea of where it is and what it looks like, but if you want to be extra careful you can plot the x and y intercepts using the standard form.

(0,8) is the y-intercept.
Factor

x-2=0 and x-4=0
x=2 and x=4 (2,0) and (4,0) are the x-intercepts.
This is what the graph looks like:

Happy Calculating!!!

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