SOLUTION: Find the vertex, maximum or minimum value, range, and intervals where it increases and decreases. f(x)=x^2 - 12

SOLUTION: Find the vertex, maximum or minimum value, range, and intervals where it increases and decreases. f(x)=x^2 - 12 - 1

Question 581166: Find the vertex, maximum or minimum value, range, and intervals where it increases and decreases. f(x)=x^2 - 12 - 1
Answer by dfrazzetto(283) (Show Source): You can put this solution on YOUR website!
f(x)=x^2 - 12x - 1, I am assuming this is what you meant to write:
vertex form, complete the square:
f(x) = x^2 -12x + 36 -1 -36
f(x) = (x - 6)^2 -37
Vertex = (6,-37)
upward facing parabola, max=infinity, minimum @ vertex (6,-37)
f'(x) = 2x -12 = 0
x=6
range = [-37, infinity)

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