Can someone help me on this problem? 
I need to write the equation of the line 
passing through the given pairs of points. 
I need to write the result in slope-intercept 
form, where possible. 

(3, -2) and (6, 4) 
Thanks,

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You need two formulas:

     y2 - y1
m = ---------
     x2 - x1

gives the slope m of the line that passes 
through the two points (x1, y1) and (x2, y2)

Then after calculating m, you substitute that 
and the values of x1 and y1 into the 
point-slope equation, which is:

y - y1 = m(x - x1)

Then solve for y.

------

Substitute (x1, y1) = (3, -2) and 
(x2, y2) = (6, 4) into

     y2 - y1
m = ---------
     x2 - x1

and you'll get m = 2

Then substitute x1 = 3, y1 = -2, and
m = 2 into

y - y1 = m(x - x1)

leaving x and y as variables,
and solve for y, and you'll get 

y = 2x - 8

This is the slope-intercept form

y = mx + b

because the slope is m = 2 and the 
y-intercept is -8.

Edwin