SOLUTION: Find the Tangent line of the curve. xy+4x-3y=0 at the point p(1,2).

Question 560124: Find the Tangent line of the curve.
xy+4x-3y=0 at the point p(1,2).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the Tangent line of the curve.
xy+4x-3y=0 at the point p(1,2).
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xy+4x-3y=0
Differentiate implicitly
xdy + ydx + 4dx - 3dy = 0
dy*(x-3) + dx*(y+4) = 0
dy/dx = -(y+4)/(x-3)
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@ (1,2) y' = -6/(-2)
= 3
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You could solve for y and get the same result.
y = 4x/(3-x)

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