SOLUTION: QUESTION: SOLVE EACH OF THE FOLLOWING SYSTEMS BY SUBSTITUION 20. 8X-4Y=16 I BELIVE YOUR SUBSTITUING FOR Y Y=2X-4 28. 4X-12Y=5 -X+ 3Y=-1

Algebra ->  Algebra  -> Graphs -> SOLUTION: QUESTION: SOLVE EACH OF THE FOLLOWING SYSTEMS BY SUBSTITUION 20. 8X-4Y=16 I BELIVE YOUR SUBSTITUING FOR Y Y=2X-4 28. 4X-12Y=5 -X+ 3Y=-1      Log On

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 Algebra: Graphs, graphing equations and inequalities Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Graphs Question 55801: QUESTION: SOLVE EACH OF THE FOLLOWING SYSTEMS BY SUBSTITUION 20. 8X-4Y=16 I BELIVE YOUR SUBSTITUING FOR Y Y=2X-4 28. 4X-12Y=5 -X+ 3Y=-1Answer by stanbon(57290)   (Show Source): You can put this solution on YOUR website!20. 8X-4Y=16 Y=2X-4 8x-4(2x-4)=16 8x-8x+16=16 0=0 This means the original problem has an infinite number of solutions ; The system of equations is true for all points on the line y=2x-4; it also means you don't have two equations, you have one. ------------- 28. 4X-12Y=5 -X+ 3Y=-1 x=3Y+1 4(3y+1)-12y=5 12y+4-12y =5 4=5 This is false, of couse. It means there is no solution to the system of equations. The two lines are parallel; they never meet in a point. cheers, Stan H.