# SOLUTION: Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y = mx+b. (-2,8; 9x = 5y + 2 The equation of the line

Algebra ->  Algebra  -> Graphs -> SOLUTION: Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y = mx+b. (-2,8; 9x = 5y + 2 The equation of the line       Log On

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 Question 553652: Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y = mx+b. (-2,8; 9x = 5y + 2 The equation of the line is y= _____ Simplfy your answer. Use intergers for any numbers in the expression.Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Equation of the line slope-intercept form y=mx+b Given Equation of the Given line 9x=5y+2 Rearrange above equation according to slope-intercept form 5y=9x-2 5y/5=(9x-2)/5 y=9/5(x)-2/5 Compare with the equation of line slope-intercept form Slope of the given = m = 9/5 Since lines are parallel their slope will be same Slope of the required line = m = 9/5 Point (-2, 8) We have a point and slope we can get easily the require line equation. Use Equation of the line point-slope form m = y2-y1/x2-x1 Put the values in above equation, we have 9/5=(y-8)/(x-(-2)) 9/5=(y-8)/(x+2) 9(x+2)=(y-8)5 9x+18=5y-40 9x+18+40=5y 9x+58=5y (9x+58)/5=5y/5 9/5(x)+58/5=y y=9/5(x)+58/5 Above equation is the equation of the required line in the form of y=mx+b