SOLUTION: Find the equation of the line (in slope-intercept form) that passes through the origin and the center of the circle 2x^2 + 2y^2 + 12x + 8y + 9 = 0.

Question 54479: Find the equation of the line (in slope-intercept form) that passes through the origin and the center of the circle 2x^2 + 2y^2 + 12x + 8y + 9 = 0.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the equation of the line (in slope-intercept form) that passes through the origin and the center of the circle 2x^2 + 2y^2 + 12x + 8y + 9 = 0.
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Put the circle equation in the center-radius form, as follows:
2(x^2+x+?) + 2(y^2+4y+?)=-9
Complete the square to get:
2(x^2+x+1/4) + 2(y^2+4y+4)= -9+(1/2)+8
As you can see, this circle has a negative radius.
Might as well stop here.
Cheers,
Stan H.
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