SOLUTION: I have to make a graph of this exponential function:
h(x) = (3/2)^x
The answer is supposed to be (-2,4/9), (0,1), (2,9/4).
I need the details of how each of these points
Algebra.Com
Question 541221: I have to make a graph of this exponential function:
h(x) = (3/2)^x
The answer is supposed to be (-2,4/9), (0,1), (2,9/4).
I need the details of how each of these points are calculated.
Thank you.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
h(x) = (3/2)^x
The answer is supposed to be (-2,4/9), (0,1), (2,9/4).
-----------------
h(-2) = (3/2)^(-2) = (2/3)^2 = 4/9
---------------------------------------
h(0) = (3/2)^0 = 1
-----------------------
H(2) = (3/2)^2 = 9/4
=========================
===============================
Cheers,
Stan H.
=
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