SOLUTION: I am trying to write an equation of the line that passes through these points (-1,3) and (2,-0.5). I am having a hard time finding the slope and solving the equation y=mx+b. I th

Question 527948: I am trying to write an equation of the line that passes through these points (-1,3) and (2,-0.5). I am having a hard time finding the slope and solving the equation y=mx+b. I think that the slope is -3.5/3, but I can't figure it out!! Please help me!!!

Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
(x,y) = (-1,3)
(x₁, y₁) = (2,-0.5)
m = (y - y₁) / (x - x₁)
.
m = (3-(-0.5)) / (-1-2) = -3.5/3
.
y = -(3.5/3)*x + b
.
Use one of the points to find 'b'.
.
3 = -(3.5/3)*(-1) + b
.
3 = 3.5/3 + b
.
b = 3-3.5/3 = 9/3 - 3.5/3 = 5.5/3
.
y = -3.5/3*x + 5.5/3
.

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