SOLUTION: What is the point-slope equation for the line that contains these points? The line contains the points (-3,4) and (2,5)

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Question 52423: What is the point-slope equation for the line that contains these points?
The line contains the points (-3,4) and (2,5)
Found 2 solutions by darq, checkley71:
Answer by darq(90) About Me  (Show Source):
You can put this solution on YOUR website!
(-3,4) and (2,5)
-3-2=-5 (calculate run)
4-5=-1 (calculate rise)
m=-1/-5=1/5 (rise/run=slope)
y=mx+b (finding y intercept; you can choose other point's domain and range too)
5=2/5+b
b=23/5

y=1%2F5%2Ax%2B23%2F5 (answer)

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
SLOPE=(5-4)/(2-(-3)) OR SLOPE=1/2+3 OR SLOPE=1/5
SOLVING FOR THE INTERCEPT WE USE THE LINE FORMULA Y=mX+b OR 4=1/5(-3)+b OR
4=-3/5+b OR 4+3/5=b OR b=4.6 THUS THE EQUATION FOR THIS LINE IS Y=1/5X+4.6