SOLUTION: Find the area of a rectangle whose length is 6 inches less than 5 times the width and whose perimeter is 8 inches more than twice the length.

Question 522392: Find the area of a rectangle whose length is 6 inches less than 5 times the width and whose perimeter is 8 inches more than twice the length.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

The perimeter of a rectangle is twice the length plus twice the width. So if the perimeter is twice the length plus 8, twice the width has to be 8. Width = 4 and you can calculate the length for yourself.

John

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