SOLUTION: What is the slope of the line containing points (3.6) and (-4, 5)?

Question 522345: What is the slope of the line containing points (3.6) and (-4, 5)?

Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
y-y₂ = m * (x-x₁)
.
6-5 = m * (3-(-4))
.
1 = m * 7
.
m = 1/7
.
y = 1/7*x + b
.
Now use one of the points to find 'b'
.
6 = 1/7*(3) + b
.
multiply by 7 to eliminate fraction
.
42 = 3 + 7b
39 = 7b
7b = 39
b = 39/7
.
y = 1/7*x + 39/7
.
or
.
7y = x + 39
-x + 7y = 39
.

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