x + 3 -------- = 3 2 Put the 3 over 1 so everything will be fractions: x + 3 3 -------- = --- 2 1 The LCD of 2 and 1 is 2. So multiply both sides by 2 over 1: 2 x + 3 2 3 --- · -------- = --- · --- 1 2 1 1 We cancel the 2's on the left and multiply the numerators 2·3, getting 6, and denominators 1·1, getting 1 on the right: 12x + 3 6 --- · -------- = --- 121 1 So we can ignore the 1's on the bottome and just have x + 3 = 6 which you should have no trouble solving. Edwin