SOLUTION: 4x+y=30 5x+6y=21

Question 519788: 4x+y=30
5x+6y=21
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
4x+y=30
5x+6y=21
.
multiply the first equation by 6 and subtract the second equation from the first
.
24x +6y = 180
5x +6y = 21
---------------
19x = 159
.
x = 159/19
.
substitute x to find y
.
4(159/19) +y = 30
.
multiply through by 19 to eliminate the fraction
.
4(159) +19y = 570
.
636 + 19y = 570
.
19y = 570-636
.
19y = -66
.
y = -66/19
.
Answer:
x = 159/19
y = -66/19
.
Check the answer:
5*(159/19) + 6*(-66/19) = 21 ??
Yes.
.
4(159/19)+(-66/19) =30 ??
Yes.
.
Done.
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