SOLUTION: The length of a rectangle is 8 more inches than twice its width. If the perimeter of the rectangle is 64 inches, what is the width of the rectangle?

Question 51723: The length of a rectangle is 8 more inches than twice its width. If the perimeter of the rectangle is 64 inches, what is the width of the rectangle?
Answer by THANApHD(104) (Show Source): You can put this solution on YOUR website!
led the width x.
then length will be 2x+8
So rectangle has perimeter which can expressed, 2(a+b), where a-legnth & b-width
So lets create the equation

AMP Parsing Error of [ = 7.33334 ]: Invalid expression '=7.33334': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .

So the width is
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