SOLUTION: A cirlce has the equation 5x^2+5y^2+30x-20y-60=0. Find the center and the radius of the circle.
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Question 516646: A cirlce has the equation 5x^2+5y^2+30x-20y-60=0. Find the center and the radius of the circle.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
^2\ +\ (y\ -\ k)^2\ =\ r^2)
is the equation of a circle centered at )
with radius 
So:
Divide through by 5
Move the constant into the RHS and put the x-terms together and the y-terms together:
Divide the coefficient on the first degree x-term by 2, square the result, add that result to both sides of the equation:
Do the same thing with the coefficient on the first degree y-term:
Factor the two perfect square trinomials in the LHS:
^2\ +\ (y\ -\ 2)^2\ =\ 25)
Now everything you need to know is right there in front of you. Hint: Rewrite your equation thus:
)^2\ +\ (y\ -\ 2)^2\ =\ 5^2)
John
My calculator said it, I believe it, that settles it
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