SOLUTION: The equation of the line that goes through the point (5,4) and is parallel to the line 2x+2y=3 can be written in the form y=mx+b where m is ... and b is....

Question 508411: The equation of the line that goes through the point (5,4) and is parallel to the line 2x+2y=3 can be written in the form y=mx+b where m is ... and b is....
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
Use the point slope form here.
Since we have a line 2x+2y=3 (which is in standard form), let's put it in y-intercept form.
Solve for y.
2y = -2x + 3
y = -x + 3/2
So the slope of this line is -1.
A line parallel to that would be -1 as well. <---- There's our slope.
We are also given the point (5,4).
So let's put it all together.
y - y1 = m(x-x1)
y - 4 = -1(x-5)
y - 4 = -x + 5
------------
y = -x + 9
y = mx + b (Recall that this is our slope-intercept form)
------------
So our m is -1 and our b is 9.
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