SOLUTION: Graph inequalities on a number line: |3x+5|>-11 This is what I did: 3x+5<11 3x+5>-11 3x+5-5<11-5 3x+5-5>-11-5 3/3x<6/3 3/3x>-16/3 x<2

Algebra.Com
Question 50594: Graph inequalities on a number line:
|3x+5|>-11
This is what I did:
3x+5<11 3x+5>-11
3x+5-5<11-5 3x+5-5>-11-5
3/3x<6/3 3/3x>-16/3
x<2 x>-16/3 or -5 1/3
Then I placed a hollow point on -5 1/3 and a hollow point on 2 and shaded the line in between. Am I correct, or just way off?

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
|3x+5|>-11
Since absolute value is always greater than or equal to
zero, won't it always be greater that -11, no matter
what that x value is?
I think the solution set is "all Real Numbers".
Cheers,
Stan H.

RELATED QUESTIONS

3x+5=2x-11 (answered by checkley77)
2(5-4x)+x=3(3x-11) (answered by wuwei96815,checkley71)
(x/5) - (11/3) = (4/3) -... (answered by ikleyn)
3x/4 +11 = 22-5 (answered by Valley11)
5(-3x+11)-7x=1 (answered by stanbon)
2| 3x + 1 | - 5 =... (answered by addingup,josgarithmetic)
-3x>0=x>3... (answered by bad-boy)
simplify: 3^4x-8/3^x+3 A. 3^5x-5 B. 3^3x-5 C. 3^3x+11 D.... (answered by stanbon)
My problem is 3x-2y=11 My x is 5 and my y is 2. 3[5]-2[2]=11 (answered by ewatrrr)