SOLUTION: I need help creating an equation for the below real life situation in which you would use a linear or straight line graph and create one to fit the example. I created the example,

Question 49741This question is from textbook Beginning Algebra
: I need help creating an equation for the below real life situation in which you would use a linear or straight line graph and create one to fit the example. I created the example, I just do not know how to put it into a equation or inequality.
Can someone please help. I am running out of time to submit my answer. I was out on the apot in a discussion class and I do not know how to respond.

Please see my example
An example of when a linear line graph may come in handy for interpreting data, would be charting a company's assets under management. My company uses one to show the amount of increase/decrease from one quarter to the next and also annually at a chosen time, showing one year to the next. For example, my company Franklin Templeton's Assets under management in 2002 was about 123 Billion, Month ending May 31, 2005 was a little over $ 417 Billion and the same time frame one year later, May 31,2006 was a little over 492 Billion ((yes... almost a trillion!). . A graph would be able to show the assets under management and how they have grown from one year to the next. People can track their personal investments from one month to the next or yearly, whichever method they prefer. However, should never be used to predict future growth because the market can fluctuate. But I think it is a perfect way to put a financial picture into play at a corporate or personal level.
This question is from textbook Beginning Algebra

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Franklin Templeton's Assets under management in 2002 was about 123 Billion, Month ending May 31, 2005 was a little over $ 417 Billion and the same time frame one year later, May 31,2006 was a little over 492 Billion.
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If you plotted these points (2,123), (5,417), (6,492), on a graph
they would not lie on the same line. So no linear equation could be
used to describe their relationship.
You could find a linear equation between any two points but that is not
what you are looking for.
With statistical methods you could generate a linear approximation (best-
least-squares-fit) for your points. It would not pass thru each of your
points but it would be the best linear approximation.
Cheers,
Stan H.
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