# SOLUTION: 2r + 5 < -1, 3t &#8805; 6t + 12,1 + 2x < 2(x-1)

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 Click here to see ALL problems on Graphs Question 49030: 2r + 5 < -1, 3t ≥ 6t + 12,1 + 2x < 2(x-1) Answer by AnlytcPhil(1539)   (Show Source): You can put this solution on YOUR website! ```2r + 5 < -1 Add -5 to both sides 2r + 5 < -1 -5 -5 --------------- 2r < -6 Divide both sides by 2, which is a positive number so we DO NOT reverse the inequality symbol 2r -6 ---- < ---- 2 2 r < -3 Sometimes this is written (-¥, -3) ------------------------------ 3t > 6t + 12 add -6t to both sides 3t > 6t + 12 -6t -6t --------------- -3t > 12 Divide both sides by -3, which is a negative number, so we DO reverse the inequality symbol from > to -3t 12 ----- < ---- -3 -3 t < -4 Sometimes this is written (-¥,-4] --------------------------------- 1 + 2x < 2(x - 1) 1 + 2x < 2x - 2 Add -2x to both sides 1 + 2x < 2x - 2 -2x -2x -------------------- 1 < -2 Since 1 is not less than -2 this has no solution. Sometimes this is written Æ Edwin```