SOLUTION: 2r + 5 < -1, 3t &#8805; 6t + 12,1 + 2x < 2(x-1)

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Question 49030: 2r + 5 < -1, 3t ≥ 6t + 12,1 + 2x < 2(x-1)
Answer by AnlytcPhil(1807)   (Show Source): You can put this solution on YOUR website!
2r + 5 < -1 

Add -5 to both sides

  2r + 5 < -1
      -5   -5
---------------
  2r     < -6

Divide both sides by 2, which is
a positive number so we DO NOT
reverse the inequality symbol

  2r     -6
 ---- < ----
   2      2

    r < -3

Sometimes this is written (-¥, -3)

------------------------------

  3t > 6t + 12

add -6t to both sides

  3t > 6t + 12
 -6t  -6t
---------------
 -3t >      12

Divide both sides by -3, which is
a negative number, so we DO
reverse the inequality symbol from
> to 

 -3t     12  
----- < ----
  -3     -3

    t < -4

Sometimes this is written (-¥,-4] 

---------------------------------



    1 + 2x < 2(x - 1)

    1 + 2x < 2x - 2

Add -2x to both sides

   1 + 2x < 2x - 2
      -2x  -2x
--------------------
   1      <    -2

Since 1 is not less than -2
this has no solution.

Sometimes this is written Æ  

Edwin
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