SOLUTION: If y varies inversely as x^2, and y = 2 when x = 4, what is the constant of variation?
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Question 48816This question is from textbook Algebra
: If y varies inversely as x^2, and y = 2 when x = 4, what is the constant of variation?
This question is from textbook Algebra
Answer by alka001(14) (Show Source): You can put this solution on YOUR website!
ans: y varies inversely as x^2
y=k/x^2 ,k is constant of variation (as y increases x^2 decreases)
y*x^2=k
Now y=2 and x=4 substituting we get
2*4^2=k
2*16=k
32=k ans.
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