SOLUTION: How do I find an equation of a parabola with a given vertex and y intercept. I need it in the form y=ax^2+bx+c form. I just need to know the proper steps to do it. Any ideas?

Question 48749: How do I find an equation of a parabola with a given vertex and y intercept. I need it in the form y=ax^2+bx+c form.
I just need to know the proper steps to do it. Any ideas?
Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
Could you send the question with the vertex and the y-intercept.
Hint: where vertex: (h,k) and y-intercept: (x,y)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do I find an equation of a parabola with a given vertex and y intercept. I need it in the form y=ax^2+bx+c form.
I just need to know the proper steps to do it. Any ideas?
-----------------
Use the vertex for of a parabola:
(x-h)^2 = 4p(y-k)
You have h and k from the given vertex.
You have x and y from the y=intercept.
You can solve for "p".
Then you can solve that equation for "y".
Cheers,
Stan H.
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