SOLUTION: I need to graph y= -4xsquared +16x-12 I also need to find the intercepts. I have completed the square, except I come up with y+76 = 4-(xsquared-4x-16) I also came up with the y

Question 48277: I need to graph y= -4xsquared +16x-12
I also need to find the intercepts.
I have completed the square, except I come up with
y+76 = 4-(xsquared-4x-16)
I also came up with the y intercept of (0, -12)
I am not sure if that is right. I also could not come up with the x intercept because I can not get the equation into vertex form. I am really confused.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y= -4x^2 +16x-12
-4(x^2-4x+4)=y+12-16
-4(x-2)^2 = y-4
(x-2)^2=-(1/4)(y-4)
----------------------------
I need to graph y= -4xsquared +16x-12
vertex at (2,4)
axis of symmetry: x=2
y-intercept: (0,-12)
x-intercepts:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=64 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1, 3. Here's your graph:

Cheers,
Stan H.
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