SOLUTION: Hi can someone help show me how this equation will look when graphed? "sketch the following graph" {{{x^2/16 -y^2/4 = 1}}}

Question 47857: Hi can someone help show me how this equation will look when graphed?
"sketch the following graph"

Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
This will look like a hyperbola.
Standard Form:
Centre(h,k)
C(0,0)
a = 4
b = 2
This hyperbola is horizontal because the value is over the value.
Asymptote: where = +-
Asymptote: = +-

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2/16 -y^2/4 = 1
The graph is a hyperbola with its center at (0,0)
intersecting the x-axis at (4,0) and (-4,0). It
opens to the right and to the left.
Cheers,
Stan H.
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