SOLUTION: I am trying to graph 8x + 7y < -56 (that should be a greater than or equal to sign) I came up with y= -8/7x - 8 Which means the rise is -8 and the then run is +7 and my y

Question 47548: I am trying to graph
8x + 7y < -56 (that should be a greater than or equal to sign)
I came up with y= -8/7x - 8
Which means the rise is -8 and the then run is +7 and my y intercept is -8
Is this correct? I am graphing system of inequalities and my first equation was x^2 + y^2 < 64 (that also is a greater than or equal to sign)
That equation gave me a solid line with a radius of 8. Do these two equations intersect at the y axis of -8?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I am trying to graph
8x + 7y < -56 (that should be a greater than or equal to sign)
I came up with y>= -8/7x - 8
Which means the rise is -8 and the then run is +7 and my y intercept is -8
Is this correct?
Yes but the graph is all points on the line because of the = sign and
also all points above the line because of the > sign.
-------------------------------------------------------
I am graphing system of inequalities and my first equation was x^2 + y^2 >= 64 (that also is a greater than or equal to sign)
That equation gave me a solid line with a radius of 8. Do these two equations intersect at the y axis of -8?
The graph of this equation is a circle with center at (0,0) and with a
radius of sqrt64=8. The graph also includes all points outside the circle
because of the > sign.
---------------------------
Cheers,
Stan H.
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