SOLUTION: determine the solution of the system:
y=x^2-6x
y+x=-4
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Question 471321: determine the solution of the system:
y=x^2-6x
y+x=-4
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
y=x^2-6x
y+x=-4
x=-4-y
y=(-4-y)2-6(-4-y)
y=16+8y+y2+24+6y
y=y2+14y+40
y2+13y+40=0
---------------
-4-x=y=x2-6x
x2-5x+4=0
(x-1)(x-4)=0
x=1 or 4
y=-3 or -8..
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