SOLUTION: what are the order pairs for y from these equations Y=2^2x {(-1, ) (0, ), (1, ), (2, ) y=(1/2)^x [(-3, ) , (-2, ) , (-1, ), (0, ), (1, , 2, ), (3, )}

Question 468477: what are the order pairs for y from these equations
Y=2^2x
{(-1, ) (0, ), (1, ), (2, )
y=(1/2)^x
[(-3, ) , (-2, ) , (-1, ), (0, ), (1, , 2, ), (3, )}
Answer by Tatiana_Stebko(1539) (Show Source): You can put this solution on YOUR website!

if x=-1 then Point (-1,0.25)
if x=0 then Point (0,1)
if x=1 then Point (1,4)
if x=2 then Point (2,16)
{(-1,0.25),(0,1),(1,4),(2,16)}
.

if x=-3 then Point (-3,8)
if x=-2 then Point (-2,4)
if x=-1 then Point (-1,2)
if x=0 then Point (0,1)
if x=1 then Point (1,0.5)
if x=2 then Point (2,0.25)
if x=3 then Point (3,0.125)
{(-3,8),(-2,4),(-1,2),(0,1),(1,0.5),(2,0.25),(3,0.125)}
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