SOLUTION: Could you please help me with this. I am not too good at finding the vertex, and graphing. Thanks so much! Huge final exam due very soon. Find the vertex,line of symmetry, and t

Question 467385: Could you please help me with this. I am not too good at finding the vertex, and graphing. Thanks so much! Huge final exam due very soon.
Find the vertex,line of symmetry, and the maximum or minimum value of f(x). Graph the function: f(x)=1/5(x+8)^2+5
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Rewrite f(x)=1/5(x+8)^2+5 as f(x)=1/5(x-(-8))^2+5

Now function is in form f(x)=a(x-h)^2+k

Vertex is (h,k). We can see that h=-8 and k=5. So the vertex is (-8,5)

The line of symmetry is the vertical line at the x coordinate of the vertex. So the line of symmetry is x = -8 (a vertical line at x=-8)

The max/min is the y value of the vertex. In this case, a=1/5, which is positive. So the y value of the vertex is a min. The min is y = 5

Graph (use a calculator or plot a series of points):

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