SOLUTION: Hello and thank you so much for your help.I got this function 7-6x-x^2=0 it's a parabola that crosses the x-axis on the points -7.0 and 1.0, the vertex it's at the point (-3.0,16).

Algebra ->  Graphs -> SOLUTION: Hello and thank you so much for your help.I got this function 7-6x-x^2=0 it's a parabola that crosses the x-axis on the points -7.0 and 1.0, the vertex it's at the point (-3.0,16).      Log On

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 Click here to see ALL problems on Graphs Question 466574: Hello and thank you so much for your help.I got this function 7-6x-x^2=0 it's a parabola that crosses the x-axis on the points -7.0 and 1.0, the vertex it's at the point (-3.0,16). I need to find the equation of the axis of symmetry for this parabola. Thank you again and have a happy 4th of July. Answer by nerdybill(7375)   (Show Source): You can put this solution on YOUR website! Hello and thank you so much for your help.I got this function 7-6x-x^2=0 it's a parabola that crosses the x-axis on the points -7.0 and 1.0, the vertex it's at the point (-3.0,16). I need to find the equation of the axis of symmetry for this parabola. Thank you again and have a happy 4th of July. . You can derive the axis of symmetry from the vertex and "inspecting" the original equation. First, Determine whether it is a "vertical" or a "horizontal" parabola. If your equation has a x^2 term -- it is a "vertical" parabola. Second, Once you know this, then you can simply use the x-coordinate of the vertex. So, the axis of symmetry is then x = -3 (vertical line crossing the x-axis at -3) . Note: the axis of symmetry is also derived by: -b/(2a) where 'a' and 'b' are the coefficients of the original equation