SOLUTION: Just don't get it... Find the equation of the line with slope -7/2 and passes through (-2,5)

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Question 465918: Just don't get it...
Find the equation of the line with slope -7/2 and passes through (-2,5)

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the slope-intercept form:
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y+=+mx+%2B+b
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In which m is the slope and b is the value on the y-axis where the graph crosses the y-axis. You are told that the slope is -7%2F2. This value can be substituted for m in the slope-intercept form to get:
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y+=+%28-7%2F2%29x+%2B+b
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You are also told that the point (-2,5) is on the graph. All the points on the graph have to satisfy the slope-intercept form. Therefore, when x is -2 and y is +5, they satisfy the slope-intercept equation. So we can substitute -2 for x and +5 for y and know that the equation must be true. When we make those substitutions, the equation becomes:
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5+=+%28-7%2F2%29%2A%28-2%29+%2B+b
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Do the multiplication of the first term on the right side of the equal sign to get:
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5+=+7+%2B+b
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Solve for b by subtracting 7 from both sides to find that:
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5+-+7+=+%2Bb
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which simplifies to:
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b+=+-2
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At this point we know that the slope is -7/2 and -2 is the value on the y-axis where the graph crosses. Therefore, substituting these two values (m and b) into the slope-intercept equation of a line results in the equation becoming:
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y+=+%28-7%2F2%29%2Ax+-2
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And this is the answer. It is an equation for the line having a slope of -7/2 and also having the point (-2,5) on the line.
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Hope this helps you to understand how to work with one of the forms of an equation that describes a specific straight line line on a graph.