SOLUTION: Factor completely 16x^3-2y^3
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Question 45673: Factor completely 16x^3-2y^3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Factor completely 16x^3-2y^3
Factor out the common factor of "2" to get:
2(8x^3-y^3)
The 8x^3 - y^3 can be written as (2x)^3 - y^3
This is the "difference of cubes" form and can be factored as follows:
(2x-y)((2x)^2-(2x)(y)+(y)^2)
Final Answer: 2(2x-y)(4x^2-2xy+y^2)
Cheers,
Stan H.
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