SOLUTION: Find an equation of the line having the given slope and containing the given poing.
m=4/5, (2,-3)
The equation of the line is y =
(Simplify your answer. Type your answer
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Question 455130: Find an equation of the line having the given slope and containing the given poing.
m=4/5, (2,-3)
The equation of the line is y =
(Simplify your answer. Type your answer in slope-intercept form. Use integers or fractions for any numbers in the expression.)
I appreciate your help with this problem.
Found 2 solutions by stanbon, mananth:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find an equation of the line having the
given slope and containing the given point.
m=4/5, (2,-3)
----
Form y = mx + b
Substitute and solve for "b":
-3 = (4/5)(2) + b
-3 = (8/5) + b
(-15/5)-(8/5) = b
b = -(23/5)
-----
The equation of the line is y = (4/5)x -(23/5)
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Cheers,
Stan H.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
slope m = 0.8
m= 0.8 ,point (2,-3)
Find b by plugging the values of m & the point in
y=mx+b
-3=1.60 +b
b=-4.6
m=0.8
Plug value of the slope and b in y = mx +b
The required equation isy=0.8x-4.6
y= 4/ 5 x-23/ 5
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