SOLUTION: please i need help, to find the equation of the line that passing through (-2,4) and having the (a) slope of 7/16. (b) parallel to the 5x-3y=3 (c) passing through the orgin (d

Question 455112: please i need help, to find the equation of the line that passing through (-2,4) and having the
(a) slope of 7/16.
(b) parallel to the 5x-3y=3
(c) passing through the orgin
(d) parallel to the y-axis.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
find the equation of the line that passing through (-2,4) and having the
(a) slope of 7/16.
Use point/slope form: y - y1 = m(x - x1)
y - 4 = (x - (-2))
y - 4 = (x + 2)
y - 4 = x +
y = x + + 4
y = x + +
y = x +
:
(b) parallel to the 5x - 3y = 3
Find the slope, put in the point/intercept form
5x - 3y = 3
-3y = -5x + 3
y had to be positive, mult both sides by -1
3y = 5x - 3
Divide both sides by 3
y = x +
y = x + 1
slope = , parallel lines have the same slopes, us the point slope form
y - 4 = (x - (-2))
y - 4 = (x + 2)
y - 4 = x +
y = x + + 4
y = x + +
y = x +
:
:
(c) passing through the origin
slope = = -2
y = -2x is the equation passes thru 0,0 and -2,4
:
:
(d) parallel to the y-axis.
x = -2
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