SOLUTION: Identify the graph of the equation and tell whether it is linear. y=1/3x I believe that the equation IS linear but I do not know the graph of the equation.

Algebra.Com
Question 449027: Identify the graph of the equation and tell whether it is linear.
y=1/3x

I believe that the equation IS linear but I do not know the graph of the equation.

Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Identify the graph of the equation and tell whether it is linear.
---
y=1/3x
--------
It is linear with a slope = 1/3.
------------------------------------
Plot two points:
If x = 0, y = 0 giving you point (0,0).
---
If x = 3, y = 1 giving you point (3,1).
----
Plot and draw a line thru them to get:


Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
y = (1/3)x Slope m = (1/3) and
y-intercept is (0,0) |m = 1/3: (y up1, x up3) (3,1) another point on this line
Plotting points and connecting with a line


RELATED QUESTIONS

Identify the graph of the equation and tell whether it is linear.... (answered by ewatrrr)
Graph the equation and tell whether it is linear X=2 See, i don't understand how to (answered by benni1013)
State whether the equation represents a linear, quadratic, or exponential function. y (answered by rapaljer)
How exactly do I determine whether this equation is linear? 3x - 5y If it is... (answered by Alan3354)
Tell whether the equation x + y = 3 is linear. Make a table of values for the equation. (answered by Fombitz)
I need help with this: Graph the equation y=6/5x and tell whether it is linear.... (answered by stanbon)
Hi, How do you tell if a function is linear? Example of a question would be: State... (answered by bam878s)
I'm suppose to graph each linear equation, but i dont know how to do that the problem... (answered by Eric Johnston)
How do I graph the linear equation... (answered by Theo,ikleyn)