SOLUTION: let F(x)=(x^2)-2x+3. find the axis of symmetry, vertex, and the x and y intercepts if they exist. sketch the graph of f.
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Question 43912: let F(x)=(x^2)-2x+3. find the axis of symmetry, vertex, and the x and y intercepts if they exist. sketch the graph of f.
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
F(x) = x^2 - 2x + 3
Vertex:((-b/2a),f(x)) ---> (1,2)
Since this parabola will be vertical, the axis of symmetry will be equal to the value of the x-value.
Axis of Symmetry:
x-intercept:
No real x-intercepts.
y-intercept:
graph:
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