You can
put this solution on YOUR website!Determine the vertex of y=x^2-8x+22. Thank you!
Put the equation in vertex form by completing the square, as follows:
y-22=x^2-8x
y-22+16=x^2-8x+4^2
y-6=(x-4)^2
Vertex is at (4,6).
This is what it looks like.
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
The discriminant -24 is less than zero. That means that there are no solutions among real numbers.
If you are a student of advanced school algebra and are aware about imaginary numbers, read on.
In the field of imaginary numbers, the square root of -24 is + or -  .
The solution is 
Here's your graph:
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Cheers,
Stan H.
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